Base | Representation |
---|---|
bin | 101101110001100001011101… |
… | …0011000010100110101110111 |
3 | 1221210121002210200111102221112 |
4 | 1123203002322120110311313 |
5 | 410233144322012311343 |
6 | 3544153530032505235 |
7 | 150544045102435112 |
oct | 13343027230246567 |
9 | 1853532720442845 |
10 | 402630541135223 |
11 | 107321720a069a5 |
12 | 391a85b56ab21b |
13 | 14387b87c5cc6b |
14 | 715d5ca609579 |
15 | 3183527344218 |
hex | 16e30ba614d77 |
402630541135223 has 2 divisors, whose sum is σ = 402630541135224. Its totient is φ = 402630541135222.
The previous prime is 402630541135169. The next prime is 402630541135241. The reversal of 402630541135223 is 322531145036204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 402630541135223 - 248 = 121155564424567 is a prime.
It is a super-3 number, since 3×4026305411352233 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (402630541135523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201315270567611 + 201315270567612.
It is an arithmetic number, because the mean of its divisors is an integer number (201315270567612).
Almost surely, 2402630541135223 is an apocalyptic number.
402630541135223 is a deficient number, since it is larger than the sum of its proper divisors (1).
402630541135223 is an equidigital number, since it uses as much as digits as its factorization.
402630541135223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 518400, while the sum is 41.
The spelling of 402630541135223 in words is "four hundred two trillion, six hundred thirty billion, five hundred forty-one million, one hundred thirty-five thousand, two hundred twenty-three".
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