Base | Representation |
---|---|
bin | 111010100110111010111… |
… | …110010001000011100001 |
3 | 112021000201212202121121222 |
4 | 322212322332101003201 |
5 | 1011441330414210223 |
6 | 12322115005424425 |
7 | 563656505462213 |
oct | 72467276210341 |
9 | 15230655677558 |
10 | 4027521241313 |
11 | 131307581a5a9 |
12 | 55068886b115 |
13 | 232a4178a7cb |
14 | dcd0c4a65b3 |
15 | 6eb721a20c8 |
hex | 3a9baf910e1 |
4027521241313 has 2 divisors, whose sum is σ = 4027521241314. Its totient is φ = 4027521241312.
The previous prime is 4027521241279. The next prime is 4027521241379. The reversal of 4027521241313 is 3131421257204.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3750837877264 + 276683364049 = 1936708^2 + 526007^2 .
It is a cyclic number.
It is not a de Polignac number, because 4027521241313 - 212 = 4027521237217 is a prime.
It is not a weakly prime, because it can be changed into another prime (4027521247313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2013760620656 + 2013760620657.
It is an arithmetic number, because the mean of its divisors is an integer number (2013760620657).
Almost surely, 24027521241313 is an apocalyptic number.
It is an amenable number.
4027521241313 is a deficient number, since it is larger than the sum of its proper divisors (1).
4027521241313 is an equidigital number, since it uses as much as digits as its factorization.
4027521241313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 35.
Adding to 4027521241313 its reverse (3131421257204), we get a palindrome (7158942498517).
The spelling of 4027521241313 in words is "four trillion, twenty-seven billion, five hundred twenty-one million, two hundred forty-one thousand, three hundred thirteen".
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