Base | Representation |
---|---|
bin | 10010010100110011001010… |
… | …11100111100010100001011 |
3 | 12021200100211011020202022002 |
4 | 21022121211130330110023 |
5 | 20240211412311210341 |
6 | 221412120404221215 |
7 | 11326240224053114 |
oct | 1112314534742413 |
9 | 167610734222262 |
10 | 40297085256971 |
11 | 119269970a2834 |
12 | 4629a1839a80b |
13 | 1963cca592c4a |
14 | 9d456448920b |
15 | 49d34657829b |
hex | 24a66573c50b |
40297085256971 has 2 divisors, whose sum is σ = 40297085256972. Its totient is φ = 40297085256970.
The previous prime is 40297085256949. The next prime is 40297085256973. The reversal of 40297085256971 is 17965258079204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40297085256971 - 218 = 40297084994827 is a prime.
Together with 40297085256973, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 40297085256898 and 40297085256907.
It is not a weakly prime, because it can be changed into another prime (40297085256973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20148542628485 + 20148542628486.
It is an arithmetic number, because the mean of its divisors is an integer number (20148542628486).
Almost surely, 240297085256971 is an apocalyptic number.
40297085256971 is a deficient number, since it is larger than the sum of its proper divisors (1).
40297085256971 is an equidigital number, since it uses as much as digits as its factorization.
40297085256971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 76204800, while the sum is 65.
The spelling of 40297085256971 in words is "forty trillion, two hundred ninety-seven billion, eighty-five million, two hundred fifty-six thousand, nine hundred seventy-one".
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