Base | Representation |
---|---|
bin | 111010101001010010000… |
… | …000101100001000100101 |
3 | 112021021021110220220000222 |
4 | 322221102000230020211 |
5 | 1012012023120024013 |
6 | 12323214250014125 |
7 | 564106345205213 |
oct | 72512200541045 |
9 | 15237243826028 |
10 | 4030055236133 |
11 | 13141561323a3 |
12 | 551075417345 |
13 | 233056760324 |
14 | dd0acc45cb3 |
15 | 6ec6e895508 |
hex | 3aa5202c225 |
4030055236133 has 2 divisors, whose sum is σ = 4030055236134. Its totient is φ = 4030055236132.
The previous prime is 4030055236069. The next prime is 4030055236147. The reversal of 4030055236133 is 3316325500304.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2560873674529 + 1469181561604 = 1600273^2 + 1212098^2 .
It is a cyclic number.
It is not a de Polignac number, because 4030055236133 - 26 = 4030055236069 is a prime.
It is a super-3 number, since 3×40300552361333 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4030055236093 and 4030055236102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4030055236433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2015027618066 + 2015027618067.
It is an arithmetic number, because the mean of its divisors is an integer number (2015027618067).
Almost surely, 24030055236133 is an apocalyptic number.
It is an amenable number.
4030055236133 is a deficient number, since it is larger than the sum of its proper divisors (1).
4030055236133 is an equidigital number, since it uses as much as digits as its factorization.
4030055236133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 35.
The spelling of 4030055236133 in words is "four trillion, thirty billion, fifty-five million, two hundred thirty-six thousand, one hundred thirty-three".
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