Base | Representation |
---|---|
bin | 10010010101001101101001… |
… | …01111011010010000011001 |
3 | 12021201201111211112211211121 |
4 | 21022212310233122100121 |
5 | 20240430020400301103 |
6 | 221422431124125241 |
7 | 11330252413556206 |
oct | 1112466457322031 |
9 | 167651454484747 |
10 | 40311300400153 |
11 | 11931a21187252 |
12 | 4630724b36821 |
13 | 196545462b983 |
14 | 9d5112366cad |
15 | 49d8c95076bd |
hex | 24a9b4bda419 |
40311300400153 has 2 divisors, whose sum is σ = 40311300400154. Its totient is φ = 40311300400152.
The previous prime is 40311300400123. The next prime is 40311300400159. The reversal of 40311300400153 is 35100400311304.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 36760005378009 + 3551295022144 = 6063003^2 + 1884488^2 .
It is a cyclic number.
It is not a de Polignac number, because 40311300400153 - 233 = 40302710465561 is a prime.
It is not a weakly prime, because it can be changed into another prime (40311300400159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20155650200076 + 20155650200077.
It is an arithmetic number, because the mean of its divisors is an integer number (20155650200077).
Almost surely, 240311300400153 is an apocalyptic number.
It is an amenable number.
40311300400153 is a deficient number, since it is larger than the sum of its proper divisors (1).
40311300400153 is an equidigital number, since it uses as much as digits as its factorization.
40311300400153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 40311300400153 its reverse (35100400311304), we get a palindrome (75411700711457).
The spelling of 40311300400153 in words is "forty trillion, three hundred eleven billion, three hundred million, four hundred thousand, one hundred fifty-three".
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