Search a number
-
+
4031213100000 = 2535531143207
BaseRepresentation
bin111010101010010111000…
…001100101101111100000
3112021101021011122110122220
4322222113001211233200
51012021411023200000
612323525211031040
7564150134660502
oct72522701455740
915241234573586
104031213100000
11131469a779689
1255133913b480
132331ac5c0888
14dd17c927d72
156ecdb35b1a0
hex3aa97065be0

4031213100000 has 288 divisors, whose sum is σ = 13269407703552. Its totient is φ = 1071508800000.

The previous prime is 4031213099989. The next prime is 4031213100049. The reversal of 4031213100000 is 13121304.

4031213100000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×40312131000002 (a number of 26 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 93278397 + ... + 93321603.

It is an arithmetic number, because the mean of its divisors is an integer number (46074332304).

Almost surely, 24031213100000 is an apocalyptic number.

4031213100000 is a gapful number since it is divisible by the number (40) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 4031213100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (6634703851776).

4031213100000 is an abundant number, since it is smaller than the sum of its proper divisors (9238194603552).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

4031213100000 is an equidigital number, since it uses as much as digits as its factorization.

4031213100000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43556 (or 43528 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 4031213100000 its reverse (13121304), we get a palindrome (4031226221304).

The spelling of 4031213100000 in words is "four trillion, thirty-one billion, two hundred thirteen million, one hundred thousand".