403123152551051 has 2 divisors, whose sum is σ = 403123152551052. Its totient is φ = 403123152551050.

The previous prime is 403123152550997. The next prime is 403123152551087. The reversal of 403123152551051 is 150155251321304.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-403123152551051 is a prime.

It is a super-2 number, since 2×403123152551051² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 403123152550996 and 403123152551014.

It is not a weakly prime, because it can be changed into another prime (403123152551351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201561576275525 + 201561576275526.

It is an arithmetic number, because the mean of its divisors is an integer number (201561576275526).

Almost surely, 2^{403123152551051} is an apocalyptic number.

403123152551051 is a deficient number, since it is larger than the sum of its proper divisors (1).

403123152551051 is an equidigital number, since it uses as much as digits as its factorization.

403123152551051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90000, while the sum is 38.

The spelling of 403123152551051 in words is "four hundred three trillion, one hundred twenty-three billion, one hundred fifty-two million, five hundred fifty-one thousand, fifty-one".