Base | Representation |
---|---|
bin | 101101110101001110110011… |
… | …0010001101011010000010111 |
3 | 1221212101211101212022011110102 |
4 | 1123222131212101223100113 |
5 | 410320022143142322403 |
6 | 3545224022052044315 |
7 | 150625630513556345 |
oct | 13352354621532027 |
9 | 1855354355264412 |
10 | 403140231214103 |
11 | 1074a88a2749049 |
12 | 3926b33b90369b |
13 | 143c3c64805706 |
14 | 717a13c758995 |
15 | 3191908a16b88 |
hex | 16ea76646b417 |
403140231214103 has 2 divisors, whose sum is σ = 403140231214104. Its totient is φ = 403140231214102.
The previous prime is 403140231214009. The next prime is 403140231214111. The reversal of 403140231214103 is 301412132041304.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 403140231214103 - 232 = 403135936246807 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (403140231214183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201570115607051 + 201570115607052.
It is an arithmetic number, because the mean of its divisors is an integer number (201570115607052).
Almost surely, 2403140231214103 is an apocalyptic number.
403140231214103 is a deficient number, since it is larger than the sum of its proper divisors (1).
403140231214103 is an equidigital number, since it uses as much as digits as its factorization.
403140231214103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 403140231214103 its reverse (301412132041304), we get a palindrome (704552363255407).
The spelling of 403140231214103 in words is "four hundred three trillion, one hundred forty billion, two hundred thirty-one million, two hundred fourteen thousand, one hundred three".
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