Base | Representation |
---|---|
bin | 10010010101011110100110… |
… | …01100010101111001011111 |
3 | 12021202121000002101012000022 |
4 | 21022233103030111321133 |
5 | 20241102140204014201 |
6 | 221430534150422355 |
7 | 11331024062442053 |
oct | 1112572314257137 |
9 | 167677002335008 |
10 | 40320401235551 |
11 | 1193587138a618 |
12 | 46324449619bb |
13 | 1966274c55a88 |
14 | 9d5736d09c63 |
15 | 49dc5d4a141b |
hex | 24abd3315e5f |
40320401235551 has 2 divisors, whose sum is σ = 40320401235552. Its totient is φ = 40320401235550.
The previous prime is 40320401235503. The next prime is 40320401235559. The reversal of 40320401235551 is 15553210402304.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40320401235551 - 230 = 40319327493727 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40320401235559) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20160200617775 + 20160200617776.
It is an arithmetic number, because the mean of its divisors is an integer number (20160200617776).
Almost surely, 240320401235551 is an apocalyptic number.
40320401235551 is a deficient number, since it is larger than the sum of its proper divisors (1).
40320401235551 is an equidigital number, since it uses as much as digits as its factorization.
40320401235551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 40320401235551 its reverse (15553210402304), we get a palindrome (55873611637855).
The spelling of 40320401235551 in words is "forty trillion, three hundred twenty billion, four hundred one million, two hundred thirty-five thousand, five hundred fifty-one".
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