40320412000081 has 2 divisors, whose sum is σ = 40320412000082. Its totient is φ = 40320412000080.

The previous prime is 40320411999961. The next prime is 40320412000093. The reversal of 40320412000081 is 18000021402304.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29850761052225 + 10469650947856 = 5463585^2 + 3235684^2 .

It is a cyclic number.

It is not a de Polignac number, because 40320412000081 - 2¹⁵ = 40320411967313 is a prime.

It is a super-2 number, since 2×40320412000081² (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40320412009081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20160206000040 + 20160206000041.

It is an arithmetic number, because the mean of its divisors is an integer number (20160206000041).

Almost surely, 2^{40320412000081} is an apocalyptic number.

It is an amenable number.

40320412000081 is a deficient number, since it is larger than the sum of its proper divisors (1).

40320412000081 is an equidigital number, since it uses as much as digits as its factorization.

40320412000081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 40320412000081 its reverse (18000021402304), we get a palindrome (58320433402385).

The spelling of 40320412000081 in words is "forty trillion, three hundred twenty billion, four hundred twelve million, eighty-one", and thus it is an aban number.