Base | Representation |
---|---|
bin | 111010101011001000011… |
… | …101001010010001110001 |
3 | 112021110101222010211122121 |
4 | 322223020131022101301 |
5 | 1012030110324123441 |
6 | 12324143354034241 |
7 | 564206525003254 |
oct | 72531035122161 |
9 | 15243358124577 |
10 | 4032042411121 |
11 | 1314a8590a37a |
12 | 55152aa18981 |
13 | 2332b236700a |
14 | dd21ab2309b |
15 | 6ed39072dd1 |
hex | 3aac874a471 |
4032042411121 has 2 divisors, whose sum is σ = 4032042411122. Its totient is φ = 4032042411120.
The previous prime is 4032042411113. The next prime is 4032042411149. The reversal of 4032042411121 is 1211142402304.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2904761200896 + 1127281210225 = 1704336^2 + 1061735^2 .
It is a cyclic number.
It is not a de Polignac number, because 4032042411121 - 23 = 4032042411113 is a prime.
It is not a weakly prime, because it can be changed into another prime (4032042411821) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016021205560 + 2016021205561.
It is an arithmetic number, because the mean of its divisors is an integer number (2016021205561).
Almost surely, 24032042411121 is an apocalyptic number.
It is an amenable number.
4032042411121 is a deficient number, since it is larger than the sum of its proper divisors (1).
4032042411121 is an equidigital number, since it uses as much as digits as its factorization.
4032042411121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 4032042411121 its reverse (1211142402304), we get a palindrome (5243184813425).
The spelling of 4032042411121 in words is "four trillion, thirty-two billion, forty-two million, four hundred eleven thousand, one hundred twenty-one".
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