Base | Representation |
---|---|
bin | 111010101011011001101… |
… | …011010110101000010001 |
3 | 112021111011002211011121012 |
4 | 322223121223112220101 |
5 | 1012031203311010101 |
6 | 12324232154540305 |
7 | 564216633621323 |
oct | 72533153265021 |
9 | 15244132734535 |
10 | 4032331344401 |
11 | 1315113a15208 |
12 | 5515ab737695 |
13 | 23332a18b859 |
14 | dd247255613 |
15 | 6ed545e7bbb |
hex | 3aad9ad6a11 |
4032331344401 has 2 divisors, whose sum is σ = 4032331344402. Its totient is φ = 4032331344400.
The previous prime is 4032331344341. The next prime is 4032331344487. The reversal of 4032331344401 is 1044431332304.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3702838124176 + 329493220225 = 1924276^2 + 574015^2 .
It is a cyclic number.
It is not a de Polignac number, because 4032331344401 - 226 = 4032264235537 is a prime.
It is not a weakly prime, because it can be changed into another prime (4032331544401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016165672200 + 2016165672201.
It is an arithmetic number, because the mean of its divisors is an integer number (2016165672201).
Almost surely, 24032331344401 is an apocalyptic number.
It is an amenable number.
4032331344401 is a deficient number, since it is larger than the sum of its proper divisors (1).
4032331344401 is an equidigital number, since it uses as much as digits as its factorization.
4032331344401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 4032331344401 its reverse (1044431332304), we get a palindrome (5076762676705).
The spelling of 4032331344401 in words is "four trillion, thirty-two billion, three hundred thirty-one million, three hundred forty-four thousand, four hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •