Base | Representation |
---|---|
bin | 111010101011011111001… |
… | …101101001011100001111 |
3 | 112021111101120120202120011 |
4 | 322223133031221130033 |
5 | 1012031401100023211 |
6 | 12324245313334051 |
7 | 564222142223035 |
oct | 72533715513417 |
9 | 15244346522504 |
10 | 4032424220431 |
11 | 1315161390362 |
12 | 551616867327 |
13 | 2333434a9899 |
14 | dd255710555 |
15 | 6ed5c841921 |
hex | 3aadf36970f |
4032424220431 has 2 divisors, whose sum is σ = 4032424220432. Its totient is φ = 4032424220430.
The previous prime is 4032424220417. The next prime is 4032424220437. The reversal of 4032424220431 is 1340224242304.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4032424220431 - 213 = 4032424212239 is a prime.
It is a super-2 number, since 2×40324242204312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4032424220393 and 4032424220402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4032424220437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016212110215 + 2016212110216.
It is an arithmetic number, because the mean of its divisors is an integer number (2016212110216).
Almost surely, 24032424220431 is an apocalyptic number.
4032424220431 is a deficient number, since it is larger than the sum of its proper divisors (1).
4032424220431 is an equidigital number, since it uses as much as digits as its factorization.
4032424220431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36864, while the sum is 31.
Adding to 4032424220431 its reverse (1340224242304), we get a palindrome (5372648462735).
The spelling of 4032424220431 in words is "four trillion, thirty-two billion, four hundred twenty-four million, two hundred twenty thousand, four hundred thirty-one".
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