Base | Representation |
---|---|
bin | 111010101100000111101… |
… | …011100001101000100101 |
3 | 112021120010220002112001201 |
4 | 322230013223201220211 |
5 | 1012034243401011123 |
6 | 12324440525122501 |
7 | 564245025032353 |
oct | 72540753415045 |
9 | 15246126075051 |
10 | 4033103141413 |
11 | 131547a642785 |
12 | 5517860b9431 |
13 | 233421048688 |
14 | dd2bb95c7d3 |
15 | 6ed9c24d5ad |
hex | 3ab07ae1a25 |
4033103141413 has 2 divisors, whose sum is σ = 4033103141414. Its totient is φ = 4033103141412.
The previous prime is 4033103141399. The next prime is 4033103141453. The reversal of 4033103141413 is 3141413013304.
4033103141413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4032317011969 + 786129444 = 2008063^2 + 28038^2 .
It is a cyclic number.
It is not a de Polignac number, because 4033103141413 - 29 = 4033103140901 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4033103141453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016551570706 + 2016551570707.
It is an arithmetic number, because the mean of its divisors is an integer number (2016551570707).
Almost surely, 24033103141413 is an apocalyptic number.
It is an amenable number.
4033103141413 is a deficient number, since it is larger than the sum of its proper divisors (1).
4033103141413 is an equidigital number, since it uses as much as digits as its factorization.
4033103141413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 4033103141413 its reverse (3141413013304), we get a palindrome (7174516154717).
The spelling of 4033103141413 in words is "four trillion, thirty-three billion, one hundred three million, one hundred forty-one thousand, four hundred thirteen".
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