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4033103141413 is a prime number
BaseRepresentation
bin111010101100000111101…
…011100001101000100101
3112021120010220002112001201
4322230013223201220211
51012034243401011123
612324440525122501
7564245025032353
oct72540753415045
915246126075051
104033103141413
11131547a642785
125517860b9431
13233421048688
14dd2bb95c7d3
156ed9c24d5ad
hex3ab07ae1a25

4033103141413 has 2 divisors, whose sum is σ = 4033103141414. Its totient is φ = 4033103141412.

The previous prime is 4033103141399. The next prime is 4033103141453. The reversal of 4033103141413 is 3141413013304.

4033103141413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4032317011969 + 786129444 = 2008063^2 + 28038^2 .

It is a cyclic number.

It is not a de Polignac number, because 4033103141413 - 29 = 4033103140901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4033103141453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016551570706 + 2016551570707.

It is an arithmetic number, because the mean of its divisors is an integer number (2016551570707).

Almost surely, 24033103141413 is an apocalyptic number.

It is an amenable number.

4033103141413 is a deficient number, since it is larger than the sum of its proper divisors (1).

4033103141413 is an equidigital number, since it uses as much as digits as its factorization.

4033103141413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 4033103141413 its reverse (3141413013304), we get a palindrome (7174516154717).

The spelling of 4033103141413 in words is "four trillion, thirty-three billion, one hundred three million, one hundred forty-one thousand, four hundred thirteen".