Base | Representation |
---|---|
bin | 111010101100001001010… |
… | …010000110010010100011 |
3 | 112021120012202200121121022 |
4 | 322230021102012102203 |
5 | 1012034322241431433 |
6 | 12324443325320055 |
7 | 564245502422426 |
oct | 72541122062243 |
9 | 15246182617538 |
10 | 4033130030243 |
11 | 1315493838756 |
12 | 55179310602b |
13 | 2334267a1522 |
14 | dd2c135b9bd |
15 | 6ed9e7b0698 |
hex | 3ab094864a3 |
4033130030243 has 2 divisors, whose sum is σ = 4033130030244. Its totient is φ = 4033130030242.
The previous prime is 4033130030239. The next prime is 4033130030299. The reversal of 4033130030243 is 3420300313304.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4033130030243 - 22 = 4033130030239 is a prime.
It is a super-2 number, since 2×40331300302432 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4033130030203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016565015121 + 2016565015122.
It is an arithmetic number, because the mean of its divisors is an integer number (2016565015122).
Almost surely, 24033130030243 is an apocalyptic number.
4033130030243 is a deficient number, since it is larger than the sum of its proper divisors (1).
4033130030243 is an equidigital number, since it uses as much as digits as its factorization.
4033130030243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 26.
Adding to 4033130030243 its reverse (3420300313304), we get a palindrome (7453430343547).
The spelling of 4033130030243 in words is "four trillion, thirty-three billion, one hundred thirty million, thirty thousand, two hundred forty-three".
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