40332510015313 has 2 divisors, whose sum is σ = 40332510015314. Its totient is φ = 40332510015312.

The previous prime is 40332510015233. The next prime is 40332510015319. The reversal of 40332510015313 is 31351001523304.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39564313860289 + 768196155024 = 6290017^2 + 876468^2 .

It is a cyclic number.

It is not a de Polignac number, because 40332510015313 - 2¹³ = 40332510007121 is a prime.

It is a super-2 number, since 2×40332510015313² (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40332510015319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20166255007656 + 20166255007657.

It is an arithmetic number, because the mean of its divisors is an integer number (20166255007657).

Almost surely, 2^{40332510015313} is an apocalyptic number.

It is an amenable number.

40332510015313 is a deficient number, since it is larger than the sum of its proper divisors (1).

40332510015313 is an equidigital number, since it uses as much as digits as its factorization.

40332510015313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 40332510015313 its reverse (31351001523304), we get a palindrome (71683511538617).

The spelling of 40332510015313 in words is "forty trillion, three hundred thirty-two billion, five hundred ten million, fifteen thousand, three hundred thirteen".