4033402004041 has 2 divisors, whose sum is σ = 4033402004042. Its totient is φ = 4033402004040.

The previous prime is 4033402004033. The next prime is 4033402004063. The reversal of 4033402004041 is 1404002043304.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3881672278416 + 151729725625 = 1970196^2 + 389525^2 .

It is a cyclic number.

It is not a de Polignac number, because 4033402004041 - 2³ = 4033402004033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4033402003997 and 4033402004015.

It is not a weakly prime, because it can be changed into another prime (4033402004011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2016701002020 + 2016701002021.

It is an arithmetic number, because the mean of its divisors is an integer number (2016701002021).

Almost surely, 2^{4033402004041} is an apocalyptic number.

It is an amenable number.

4033402004041 is a deficient number, since it is larger than the sum of its proper divisors (1).

4033402004041 is an equidigital number, since it uses as much as digits as its factorization.

4033402004041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 25.

Adding to 4033402004041 its reverse (1404002043304), we get a palindrome (5437404047345).

The spelling of 4033402004041 in words is "four trillion, thirty-three billion, four hundred two million, four thousand, forty-one".