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40334523434449 is a prime number
BaseRepresentation
bin10010010101111000111001…
…11100010000010111010001
312021210221110021210012221221
421022330130330100113101
520241320100444400244
6221441231350245041
711332034043240436
oct1112743474202721
9167727407705857
1040334523434449
1111940858a61682
124635126356781
1319676b597b69a
149d62b6711b8d
1549e2d81c1784
hex24af1cf105d1

40334523434449 has 2 divisors, whose sum is σ = 40334523434450. Its totient is φ = 40334523434448.

The previous prime is 40334523434441. The next prime is 40334523434501. The reversal of 40334523434449 is 94443432543304.

It is an a-pointer prime, because the next prime (40334523434501) can be obtained adding 40334523434449 to its sum of digits (52).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 40334375374225 + 148060224 = 6350935^2 + 12168^2 .

It is a cyclic number.

It is not a de Polignac number, because 40334523434449 - 23 = 40334523434441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 40334523434396 and 40334523434405.

It is not a weakly prime, because it can be changed into another prime (40334523434441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20167261717224 + 20167261717225.

It is an arithmetic number, because the mean of its divisors is an integer number (20167261717225).

Almost surely, 240334523434449 is an apocalyptic number.

It is an amenable number.

40334523434449 is a deficient number, since it is larger than the sum of its proper divisors (1).

40334523434449 is an equidigital number, since it uses as much as digits as its factorization.

40334523434449 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 29859840, while the sum is 52.

The spelling of 40334523434449 in words is "forty trillion, three hundred thirty-four billion, five hundred twenty-three million, four hundred thirty-four thousand, four hundred forty-nine".