40341281 has 2 divisors, whose sum is σ = 40341282. Its totient is φ = 40341280.

The previous prime is 40341269. The next prime is 40341293. The reversal of 40341281 is 18214304.

40341281 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (40341269) and next prime (40341293).

It can be written as a sum of positive squares in only one way, i.e., 31460881 + 8880400 = 5609^2 + 2980^2 .

It is a cyclic number.

It is not a de Polignac number, because 40341281 - 2¹⁰ = 40340257 is a prime.

It is a super-2 number, since 2×40341281² = 3254837905441922, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (40341251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20170640 + 20170641.

It is an arithmetic number, because the mean of its divisors is an integer number (20170641).

Almost surely, 2^40341281 is an apocalyptic number.

It is an amenable number.

40341281 is a deficient number, since it is larger than the sum of its proper divisors (1).

40341281 is an equidigital number, since it uses as much as digits as its factorization.

40341281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

The square root of 40341281 is about 6351.4786467405. The cubic root of 40341281 is about 342.9650733532.

Adding to 40341281 its reverse (18214304), we get a palindrome (58555585).

The spelling of 40341281 in words is "forty million, three hundred forty-one thousand, two hundred eighty-one".