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4034130114383 is a prime number
BaseRepresentation
bin111010101101000100111…
…001000111011101001111
3112021122210110112011010122
4322231010321013131033
51012043344302130013
612325130452455155
7564312335123555
oct72550471073517
915248713464118
104034130114383
111315957309776
12551a1201a4bb
13233555a3aaa5
14dd3780cbbd5
156ee0c4aba08
hex3ab44e4774f

4034130114383 has 2 divisors, whose sum is σ = 4034130114384. Its totient is φ = 4034130114382.

The previous prime is 4034130114379. The next prime is 4034130114433. The reversal of 4034130114383 is 3834110314304.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4034130114383 - 22 = 4034130114379 is a prime.

It is a super-3 number, since 3×40341301143833 (a number of 39 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4034130114583) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2017065057191 + 2017065057192.

It is an arithmetic number, because the mean of its divisors is an integer number (2017065057192).

Almost surely, 24034130114383 is an apocalyptic number.

4034130114383 is a deficient number, since it is larger than the sum of its proper divisors (1).

4034130114383 is an equidigital number, since it uses as much as digits as its factorization.

4034130114383 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 41472, while the sum is 35.

Adding to 4034130114383 its reverse (3834110314304), we get a palindrome (7868240428687).

The spelling of 4034130114383 in words is "four trillion, thirty-four billion, one hundred thirty million, one hundred fourteen thousand, three hundred eighty-three".