Base | Representation |
---|---|
bin | 111010101101000100111… |
… | …001000111011101001111 |
3 | 112021122210110112011010122 |
4 | 322231010321013131033 |
5 | 1012043344302130013 |
6 | 12325130452455155 |
7 | 564312335123555 |
oct | 72550471073517 |
9 | 15248713464118 |
10 | 4034130114383 |
11 | 1315957309776 |
12 | 551a1201a4bb |
13 | 233555a3aaa5 |
14 | dd3780cbbd5 |
15 | 6ee0c4aba08 |
hex | 3ab44e4774f |
4034130114383 has 2 divisors, whose sum is σ = 4034130114384. Its totient is φ = 4034130114382.
The previous prime is 4034130114379. The next prime is 4034130114433. The reversal of 4034130114383 is 3834110314304.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4034130114383 - 22 = 4034130114379 is a prime.
It is a super-3 number, since 3×40341301143833 (a number of 39 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4034130114583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2017065057191 + 2017065057192.
It is an arithmetic number, because the mean of its divisors is an integer number (2017065057192).
Almost surely, 24034130114383 is an apocalyptic number.
4034130114383 is a deficient number, since it is larger than the sum of its proper divisors (1).
4034130114383 is an equidigital number, since it uses as much as digits as its factorization.
4034130114383 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 35.
Adding to 4034130114383 its reverse (3834110314304), we get a palindrome (7868240428687).
The spelling of 4034130114383 in words is "four trillion, thirty-four billion, one hundred thirty million, one hundred fourteen thousand, three hundred eighty-three".
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