Base | Representation |
---|---|
bin | 10010010110010000001011… |
… | …11011000011011001011101 |
3 | 12021212010201100022111201212 |
4 | 21023020011323003121131 |
5 | 20242021200132120432 |
6 | 221451055513114205 |
7 | 11332655551441232 |
oct | 1113100573033135 |
9 | 167763640274655 |
10 | 40347022145117 |
11 | 11946092179a26 |
12 | 46376340b8965 |
13 | 196892823647c |
14 | 9d6b4066b789 |
15 | 49e7ba6032b2 |
hex | 24b205ec365d |
40347022145117 has 2 divisors, whose sum is σ = 40347022145118. Its totient is φ = 40347022145116.
The previous prime is 40347022145077. The next prime is 40347022145159. The reversal of 40347022145117 is 71154122074304.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23081384967481 + 17265637177636 = 4804309^2 + 4155194^2 .
It is a cyclic number.
It is not a de Polignac number, because 40347022145117 - 238 = 40072144238173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40347022145317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20173511072558 + 20173511072559.
It is an arithmetic number, because the mean of its divisors is an integer number (20173511072559).
Almost surely, 240347022145117 is an apocalyptic number.
It is an amenable number.
40347022145117 is a deficient number, since it is larger than the sum of its proper divisors (1).
40347022145117 is an equidigital number, since it uses as much as digits as its factorization.
40347022145117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 188160, while the sum is 41.
The spelling of 40347022145117 in words is "forty trillion, three hundred forty-seven billion, twenty-two million, one hundred forty-five thousand, one hundred seventeen".
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