Base | Representation |
---|---|
bin | 10010010110010001010110… |
… | …11010000111101010110011 |
3 | 12021212012100011200222122122 |
4 | 21023020223122013222303 |
5 | 20242023442131433232 |
6 | 221451242140424455 |
7 | 11333010256140551 |
oct | 1113105332075263 |
9 | 167765304628578 |
10 | 40347651046067 |
11 | 11946385177582 |
12 | 463778a84812b |
13 | 19689c8610a01 |
14 | 9d6b9ddb8bd1 |
15 | 49e80592e312 |
hex | 24b22b687ab3 |
40347651046067 has 2 divisors, whose sum is σ = 40347651046068. Its totient is φ = 40347651046066.
The previous prime is 40347651045953. The next prime is 40347651046097. The reversal of 40347651046067 is 76064015674304.
40347651046067 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40347651046067 - 210 = 40347651045043 is a prime.
It is not a weakly prime, because it can be changed into another prime (40347651046097) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20173825523033 + 20173825523034.
It is an arithmetic number, because the mean of its divisors is an integer number (20173825523034).
Almost surely, 240347651046067 is an apocalyptic number.
40347651046067 is a deficient number, since it is larger than the sum of its proper divisors (1).
40347651046067 is an equidigital number, since it uses as much as digits as its factorization.
40347651046067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10160640, while the sum is 53.
The spelling of 40347651046067 in words is "forty trillion, three hundred forty-seven billion, six hundred fifty-one million, forty-six thousand, sixty-seven".
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