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40351212514621 is a prime number
BaseRepresentation
bin10010010110010111111111…
…01100000010110100111101
312021212112112101020100001101
421023023333230002310331
520242103240400431441
6221453031403213101
711333164443132031
oct1113137754026475
9167775471210041
1040351212514621
1111947942568618
124638403517191
13196914541c858
149d701adb81c1
1549e96342e231
hex24b2ffb02d3d

40351212514621 has 2 divisors, whose sum is σ = 40351212514622. Its totient is φ = 40351212514620.

The previous prime is 40351212514589. The next prime is 40351212514637. The reversal of 40351212514621 is 12641521215304.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39927372453721 + 423840060900 = 6318811^2 + 651030^2 .

It is a cyclic number.

It is not a de Polignac number, because 40351212514621 - 25 = 40351212514589 is a prime.

It is a super-2 number, since 2×403512125146212 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40351212514681) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20175606257310 + 20175606257311.

It is an arithmetic number, because the mean of its divisors is an integer number (20175606257311).

Almost surely, 240351212514621 is an apocalyptic number.

It is an amenable number.

40351212514621 is a deficient number, since it is larger than the sum of its proper divisors (1).

40351212514621 is an equidigital number, since it uses as much as digits as its factorization.

40351212514621 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 57600, while the sum is 37.

Adding to 40351212514621 its reverse (12641521215304), we get a palindrome (52992733729925).

The spelling of 40351212514621 in words is "forty trillion, three hundred fifty-one billion, two hundred twelve million, five hundred fourteen thousand, six hundred twenty-one".