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40376554126453 is a prime number
BaseRepresentation
bin10010010111000111001100…
…01010100111110001110101
312021221221221110221121012101
421023203212022213301311
520243012140324021303
6221512422150022101
711335052436233206
oct1113434612476165
9167857843847171
1040376554126453
111195766720a676
1246412b6347931
13196b65366323c
149d83428875ad
154a04480ced1d
hex24b8e62a7c75

40376554126453 has 2 divisors, whose sum is σ = 40376554126454. Its totient is φ = 40376554126452.

The previous prime is 40376554126411. The next prime is 40376554126471. The reversal of 40376554126453 is 35462145567304.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37136921316049 + 3239632810404 = 6094007^2 + 1799898^2 .

It is a cyclic number.

It is not a de Polignac number, because 40376554126453 - 213 = 40376554118261 is a prime.

It is a super-2 number, since 2×403765541264532 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40376554126394 and 40376554126403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40376554126253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20188277063226 + 20188277063227.

It is an arithmetic number, because the mean of its divisors is an integer number (20188277063227).

Almost surely, 240376554126453 is an apocalyptic number.

It is an amenable number.

40376554126453 is a deficient number, since it is larger than the sum of its proper divisors (1).

40376554126453 is an equidigital number, since it uses as much as digits as its factorization.

40376554126453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36288000, while the sum is 55.

The spelling of 40376554126453 in words is "forty trillion, three hundred seventy-six billion, five hundred fifty-four million, one hundred twenty-six thousand, four hundred fifty-three".