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40400313243133 is a prime number
BaseRepresentation
bin10010010111110011011100…
…10100011101010111111101
312022001020021021220210002211
421023321232110131113331
520243404320142240013
6221531351522220421
711336553265342024
oct1113715624352775
9168036237823084
1040400313243133
1111966749656698
124645a271b4711
13197096ba8c66c
149d95580db8bb
154a0d88d8d23d
hex24be6e51d5fd

40400313243133 has 2 divisors, whose sum is σ = 40400313243134. Its totient is φ = 40400313243132.

The previous prime is 40400313243109. The next prime is 40400313243167. The reversal of 40400313243133 is 33134231300404.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29216759994009 + 11183553249124 = 5405253^2 + 3344182^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40400313243133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 40400313243095 and 40400313243104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40400313241133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20200156621566 + 20200156621567.

It is an arithmetic number, because the mean of its divisors is an integer number (20200156621567).

Almost surely, 240400313243133 is an apocalyptic number.

It is an amenable number.

40400313243133 is a deficient number, since it is larger than the sum of its proper divisors (1).

40400313243133 is an equidigital number, since it uses as much as digits as its factorization.

40400313243133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 40400313243133 its reverse (33134231300404), we get a palindrome (73534544543537).

The spelling of 40400313243133 in words is "forty trillion, four hundred billion, three hundred thirteen million, two hundred forty-three thousand, one hundred thirty-three".