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40402775412511 is a prime number
BaseRepresentation
bin10010010111111000000010…
…00100111000111100011111
312022001110121212220221112021
421023330001010320330133
520243424341001200021
6221532440115121011
711340001303416301
oct1113740104707437
9168043555827467
1040402775412511
11119677a2470a16
1246463b38a3167
131970c71c04815
149d970d101971
154a0e800e4c41
hex24bf01138f1f

40402775412511 has 2 divisors, whose sum is σ = 40402775412512. Its totient is φ = 40402775412510.

The previous prime is 40402775412473. The next prime is 40402775412539. The reversal of 40402775412511 is 11521457720404.

40402775412511 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40402775412511 is a prime.

It is a super-2 number, since 2×404027754125112 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40402775412011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20201387706255 + 20201387706256.

It is an arithmetic number, because the mean of its divisors is an integer number (20201387706256).

Almost surely, 240402775412511 is an apocalyptic number.

40402775412511 is a deficient number, since it is larger than the sum of its proper divisors (1).

40402775412511 is an equidigital number, since it uses as much as digits as its factorization.

40402775412511 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 313600, while the sum is 43.

The spelling of 40402775412511 in words is "forty trillion, four hundred two billion, seven hundred seventy-five million, four hundred twelve thousand, five hundred eleven".