Base | Representation |
---|---|
bin | 111010110010110110101… |
… | …011110101000100111111 |
3 | 112022020210211121102020001 |
4 | 322302312223311010333 |
5 | 1012144101023414101 |
6 | 12332034235535131 |
7 | 564622151030233 |
oct | 72626653650477 |
9 | 15266724542201 |
10 | 4040334201151 |
11 | 1318550363a06 |
12 | 5530638ba4a7 |
13 | 234004192051 |
14 | dd7a60645c3 |
15 | 70171ea9901 |
hex | 3acb6af513f |
4040334201151 has 2 divisors, whose sum is σ = 4040334201152. Its totient is φ = 4040334201150.
The previous prime is 4040334201119. The next prime is 4040334201271. The reversal of 4040334201151 is 1511024330404.
4040334201151 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4040334201151 - 25 = 4040334201119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4040334208151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2020167100575 + 2020167100576.
It is an arithmetic number, because the mean of its divisors is an integer number (2020167100576).
Almost surely, 24040334201151 is an apocalyptic number.
4040334201151 is a deficient number, since it is larger than the sum of its proper divisors (1).
4040334201151 is an equidigital number, since it uses as much as digits as its factorization.
4040334201151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 4040334201151 its reverse (1511024330404), we get a palindrome (5551358531555).
The spelling of 4040334201151 in words is "four trillion, forty billion, three hundred thirty-four million, two hundred one thousand, one hundred fifty-one".
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