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4040411231413 is a prime number
BaseRepresentation
bin111010110010111011010…
…001101011010010110101
3112022021000012112221212201
4322302323101223102311
51012144230233401123
612332050030544501
7564624104544244
oct72627321532265
915267005487781
104040411231413
11131858a896987
12553085668131
1323401712279b
14dd7b239695b
1570178b235ad
hex3acbb46b4b5

4040411231413 has 2 divisors, whose sum is σ = 4040411231414. Its totient is φ = 4040411231412.

The previous prime is 4040411231401. The next prime is 4040411231431. The reversal of 4040411231413 is 3141321140404.

Together with next prime (4040411231431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2320266190564 + 1720145040849 = 1523242^2 + 1311543^2 .

It is a cyclic number.

It is not a de Polignac number, because 4040411231413 - 221 = 4040409134261 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4040411231473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2020205615706 + 2020205615707.

It is an arithmetic number, because the mean of its divisors is an integer number (2020205615707).

Almost surely, 24040411231413 is an apocalyptic number.

It is an amenable number.

4040411231413 is a deficient number, since it is larger than the sum of its proper divisors (1).

4040411231413 is an equidigital number, since it uses as much as digits as its factorization.

4040411231413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 4040411231413 its reverse (3141321140404), we get a palindrome (7181732371817).

The spelling of 4040411231413 in words is "four trillion, forty billion, four hundred eleven million, two hundred thirty-one thousand, four hundred thirteen".