Base | Representation |
---|---|
bin | 111010110011101011001… |
… | …010010100101111111111 |
3 | 112022100002012020211201011 |
4 | 322303223022110233333 |
5 | 1012202401420013211 |
6 | 12332301450100051 |
7 | 564653031263155 |
oct | 72635312245777 |
9 | 15270065224634 |
10 | 4041214610431 |
11 | 1318962325489 |
12 | 55326a71a627 |
13 | 2341146b969b |
14 | dd84ad613d5 |
15 | 701c4416921 |
hex | 3aceb294bff |
4041214610431 has 2 divisors, whose sum is σ = 4041214610432. Its totient is φ = 4041214610430.
The previous prime is 4041214610399. The next prime is 4041214610467. The reversal of 4041214610431 is 1340164121404.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4041214610431 - 25 = 4041214610399 is a prime.
It is a super-2 number, since 2×40412146104312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4041214610393 and 4041214610402.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4041214610731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2020607305215 + 2020607305216.
It is an arithmetic number, because the mean of its divisors is an integer number (2020607305216).
Almost surely, 24041214610431 is an apocalyptic number.
4041214610431 is a deficient number, since it is larger than the sum of its proper divisors (1).
4041214610431 is an equidigital number, since it uses as much as digits as its factorization.
4041214610431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 4041214610431 its reverse (1340164121404), we get a palindrome (5381378731835).
The spelling of 4041214610431 in words is "four trillion, forty-one billion, two hundred fourteen million, six hundred ten thousand, four hundred thirty-one".
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