Base | Representation |
---|---|
bin | 111010110011110001100… |
… | …001011100101001110011 |
3 | 112022100100122002000212012 |
4 | 322303301201130221303 |
5 | 1012203111230213121 |
6 | 12332320221353135 |
7 | 564655465364543 |
oct | 72636141345163 |
9 | 15270318060765 |
10 | 4041321335411 |
11 | 1318a0759a548 |
12 | 55329a4087ab |
13 | 234130846169 |
14 | dd85b1c3323 |
15 | 701cd998c5b |
hex | 3acf185ca73 |
4041321335411 has 2 divisors, whose sum is σ = 4041321335412. Its totient is φ = 4041321335410.
The previous prime is 4041321335333. The next prime is 4041321335431. The reversal of 4041321335411 is 1145331231404.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4041321335411 - 222 = 4041317141107 is a prime.
It is not a weakly prime, because it can be changed into another prime (4041321335431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2020660667705 + 2020660667706.
It is an arithmetic number, because the mean of its divisors is an integer number (2020660667706).
Almost surely, 24041321335411 is an apocalyptic number.
4041321335411 is a deficient number, since it is larger than the sum of its proper divisors (1).
4041321335411 is an equidigital number, since it uses as much as digits as its factorization.
4041321335411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 4041321335411 its reverse (1145331231404), we get a palindrome (5186652566815).
The spelling of 4041321335411 in words is "four trillion, forty-one billion, three hundred twenty-one million, three hundred thirty-five thousand, four hundred eleven".
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