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4042110000023 is a prime number
BaseRepresentation
bin111010110100100000100…
…001111101101110010111
3112022102101121002100022122
4322310200201331232113
51012211220130000043
612332530353250155
7565014153050354
oct72644041755627
915272347070278
104042110000023
111319281798987
1255347a56395b
1323422805a704
14dd8d3c3b62b
1570227d32368
hex3ad2087db97

4042110000023 has 2 divisors, whose sum is σ = 4042110000024. Its totient is φ = 4042110000022.

The previous prime is 4042110000011. The next prime is 4042110000083. The reversal of 4042110000023 is 3200000112404.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4042110000023 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4042109999956 and 4042110000010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4042110000083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021055000011 + 2021055000012.

It is an arithmetic number, because the mean of its divisors is an integer number (2021055000012).

Almost surely, 24042110000023 is an apocalyptic number.

4042110000023 is a deficient number, since it is larger than the sum of its proper divisors (1).

4042110000023 is an equidigital number, since it uses as much as digits as its factorization.

4042110000023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 17.

Adding to 4042110000023 its reverse (3200000112404), we get a palindrome (7242110112427).

The spelling of 4042110000023 in words is "four trillion, forty-two billion, one hundred ten million, twenty-three", and thus it is an aban number.