Base | Representation |
---|---|
bin | 111010110100100001010… |
… | …001010110100100000011 |
3 | 112022102102110110110210112 |
4 | 322310201101112210003 |
5 | 1012211231320010111 |
6 | 12332531515421535 |
7 | 565014363456524 |
oct | 72644121264403 |
9 | 15272373413715 |
10 | 4042122422531 |
11 | 1319288803116 |
12 | 5534827548ab |
13 | 23422a7b9acb |
14 | dd8d575284b |
15 | 70228e87e8b |
hex | 3ad21456903 |
4042122422531 has 2 divisors, whose sum is σ = 4042122422532. Its totient is φ = 4042122422530.
The previous prime is 4042122422449. The next prime is 4042122422609. The reversal of 4042122422531 is 1352242212404.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4042122422531 - 218 = 4042122160387 is a prime.
It is a super-3 number, since 3×40421224225313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (4042122422731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021061211265 + 2021061211266.
It is an arithmetic number, because the mean of its divisors is an integer number (2021061211266).
Almost surely, 24042122422531 is an apocalyptic number.
4042122422531 is a deficient number, since it is larger than the sum of its proper divisors (1).
4042122422531 is an equidigital number, since it uses as much as digits as its factorization.
4042122422531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30720, while the sum is 32.
Adding to 4042122422531 its reverse (1352242212404), we get a palindrome (5394364634935).
The spelling of 4042122422531 in words is "four trillion, forty-two billion, one hundred twenty-two million, four hundred twenty-two thousand, five hundred thirty-one".
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