Base | Representation |
---|---|
bin | 111010110100110101100… |
… | …010100001000011011011 |
3 | 112022110022011022111002222 |
4 | 322310311202201003123 |
5 | 1012212430342410032 |
6 | 12333025344014255 |
7 | 565025663005631 |
oct | 72646542410333 |
9 | 15273264274088 |
10 | 4042462466267 |
11 | 1319442747aa5 |
12 | 55355860138b |
13 | 234283098314 |
14 | dd92898b351 |
15 | 70248c56a12 |
hex | 3ad358a10db |
4042462466267 has 2 divisors, whose sum is σ = 4042462466268. Its totient is φ = 4042462466266.
The previous prime is 4042462466171. The next prime is 4042462466281. The reversal of 4042462466267 is 7626642642404.
4042462466267 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4042462466267 - 210 = 4042462465243 is a prime.
It is a super-2 number, since 2×40424624662672 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4042462466167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021231233133 + 2021231233134.
It is an arithmetic number, because the mean of its divisors is an integer number (2021231233134).
Almost surely, 24042462466267 is an apocalyptic number.
4042462466267 is a deficient number, since it is larger than the sum of its proper divisors (1).
4042462466267 is an equidigital number, since it uses as much as digits as its factorization.
4042462466267 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18579456, while the sum is 53.
The spelling of 4042462466267 in words is "four trillion, forty-two billion, four hundred sixty-two million, four hundred sixty-six thousand, two hundred sixty-seven".
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