Base | Representation |
---|---|
bin | 111010110101011101000… |
… | …101111010011001000001 |
3 | 112022112000101222100210111 |
4 | 322311131011322121001 |
5 | 1012220310232302023 |
6 | 12333215251031321 |
7 | 565051301304235 |
oct | 72653505723101 |
9 | 15275011870714 |
10 | 4043126056513 |
11 | 1319753289195 |
12 | 55370289b541 |
13 | 23435a6ca07b |
14 | dd98cb685c5 |
15 | 7028713600d |
hex | 3ad5d17a641 |
4043126056513 has 2 divisors, whose sum is σ = 4043126056514. Its totient is φ = 4043126056512.
The previous prime is 4043126056493. The next prime is 4043126056553. The reversal of 4043126056513 is 3156506213404.
It is an a-pointer prime, because the next prime (4043126056553) can be obtained adding 4043126056513 to its sum of digits (40).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2810608661169 + 1232517395344 = 1676487^2 + 1110188^2 .
It is a cyclic number.
It is not a de Polignac number, because 4043126056513 - 25 = 4043126056481 is a prime.
It is not a weakly prime, because it can be changed into another prime (4043126056553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021563028256 + 2021563028257.
It is an arithmetic number, because the mean of its divisors is an integer number (2021563028257).
Almost surely, 24043126056513 is an apocalyptic number.
It is an amenable number.
4043126056513 is a deficient number, since it is larger than the sum of its proper divisors (1).
4043126056513 is an equidigital number, since it uses as much as digits as its factorization.
4043126056513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 40.
The spelling of 4043126056513 in words is "four trillion, forty-three billion, one hundred twenty-six million, fifty-six thousand, five hundred thirteen".
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