Base | Representation |
---|---|
bin | 100101101010000000… |
… | …001010001001001111 |
3 | 10212100212001221001112 |
4 | 211222000022021033 |
5 | 1130301340211421 |
6 | 30324050202235 |
7 | 2630653644431 |
oct | 455200121117 |
9 | 125325057045 |
10 | 40433132111 |
11 | 161694a3669 |
12 | 7a04b8337b |
13 | 3a74a24658 |
14 | 1d57d18651 |
15 | 10b9a4245b |
hex | 96a00a24f |
40433132111 has 2 divisors, whose sum is σ = 40433132112. Its totient is φ = 40433132110.
The previous prime is 40433132107. The next prime is 40433132227. The reversal of 40433132111 is 11123133404.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40433132111 - 22 = 40433132107 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40433132101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20216566055 + 20216566056.
It is an arithmetic number, because the mean of its divisors is an integer number (20216566056).
Almost surely, 240433132111 is an apocalyptic number.
40433132111 is a deficient number, since it is larger than the sum of its proper divisors (1).
40433132111 is an equidigital number, since it uses as much as digits as its factorization.
40433132111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 40433132111 its reverse (11123133404), we get a palindrome (51556265515).
The spelling of 40433132111 in words is "forty billion, four hundred thirty-three million, one hundred thirty-two thousand, one hundred eleven".
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