404332111320031 has 2 divisors, whose sum is σ = 404332111320032. Its totient is φ = 404332111320030.

The previous prime is 404332111320013. The next prime is 404332111320223. The reversal of 404332111320031 is 130023111233404.

Together with previous prime (404332111320013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 404332111320031 - 2¹¹ = 404332111317983 is a prime.

It is a super-2 number, since 2×404332111320031² (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (404332111350031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202166055660015 + 202166055660016.

It is an arithmetic number, because the mean of its divisors is an integer number (202166055660016).

Almost surely, 2^{404332111320031} is an apocalyptic number.

404332111320031 is a deficient number, since it is larger than the sum of its proper divisors (1).

404332111320031 is an equidigital number, since it uses as much as digits as its factorization.

404332111320031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 404332111320031 its reverse (130023111233404), we get a palindrome (534355222553435).

The spelling of 404332111320031 in words is "four hundred four trillion, three hundred thirty-two billion, one hundred eleven million, three hundred twenty thousand, thirty-one".