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4043534501243 is a prime number
BaseRepresentation
bin111010110101110101011…
…100000000010101111011
3112022120001212112111122002
4322311311130000111323
51012222124313014433
612333324001251215
7565064361110216
oct72656534002573
915276055474562
104043534501243
1113199428a1816
125537b7633b0b
132343c4207343
14dd9cb0ca77d
15702ace169e8
hex3ad7570057b

4043534501243 has 2 divisors, whose sum is σ = 4043534501244. Its totient is φ = 4043534501242.

The previous prime is 4043534501231. The next prime is 4043534501297. The reversal of 4043534501243 is 3421054353404.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4043534501243 - 232 = 4039239533947 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 4043534501197 and 4043534501206.

It is not a weakly prime, because it can be changed into another prime (4043534581243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2021767250621 + 2021767250622.

It is an arithmetic number, because the mean of its divisors is an integer number (2021767250622).

Almost surely, 24043534501243 is an apocalyptic number.

4043534501243 is a deficient number, since it is larger than the sum of its proper divisors (1).

4043534501243 is an equidigital number, since it uses as much as digits as its factorization.

4043534501243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 345600, while the sum is 38.

Adding to 4043534501243 its reverse (3421054353404), we get a palindrome (7464588854647).

The spelling of 4043534501243 in words is "four trillion, forty-three billion, five hundred thirty-four million, five hundred one thousand, two hundred forty-three".