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404444310012241 is a prime number
BaseRepresentation
bin101101111110101110000011…
…1011011100000000101010001
31222001000111110100122000212021
41123331130013123200011101
5411002403421330342431
63552103052342331441
7151122065014503562
oct13375340733400521
91861014410560767
10404444310012241
11107960961184694
1239440025129b81
1314489c1c950875
1471c32cd8ca169
1531b57d0a79b11
hex16fd7076e0151

404444310012241 has 2 divisors, whose sum is σ = 404444310012242. Its totient is φ = 404444310012240.

The previous prime is 404444310012233. The next prime is 404444310012269. The reversal of 404444310012241 is 142210013444404.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 337058205131025 + 67386104881216 = 18359145^2 + 8208904^2 .

It is a cyclic number.

It is not a de Polignac number, because 404444310012241 - 23 = 404444310012233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 404444310012197 and 404444310012206.

It is not a weakly prime, because it can be changed into another prime (404444310012221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202222155006120 + 202222155006121.

It is an arithmetic number, because the mean of its divisors is an integer number (202222155006121).

Almost surely, 2404444310012241 is an apocalyptic number.

It is an amenable number.

404444310012241 is a deficient number, since it is larger than the sum of its proper divisors (1).

404444310012241 is an equidigital number, since it uses as much as digits as its factorization.

404444310012241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 49152, while the sum is 34.

Adding to 404444310012241 its reverse (142210013444404), we get a palindrome (546654323456645).

The spelling of 404444310012241 in words is "four hundred four trillion, four hundred forty-four billion, three hundred ten million, twelve thousand, two hundred forty-one".