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40445215441 is a prime number
BaseRepresentation
bin100101101010101110…
…010000001011010001
310212101200210211021021
4211222232100023101
51130312433343231
630325201155441
72631161442001
oct455256201321
9125350724237
1040445215441
11161752a6a94
127a0902bb81
133a77395557
141d59782001
1510bab2c811
hex96ab902d1

40445215441 has 2 divisors, whose sum is σ = 40445215442. Its totient is φ = 40445215440.

The previous prime is 40445215427. The next prime is 40445215537. The reversal of 40445215441 is 14451254404.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 33118540225 + 7326675216 = 181985^2 + 85596^2 .

It is a cyclic number.

It is not a de Polignac number, because 40445215441 - 219 = 40444691153 is a prime.

It is a super-3 number, since 3×404452154413 (a number of 33 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40445215397 and 40445215406.

It is not a weakly prime, because it can be changed into another prime (40445215541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20222607720 + 20222607721.

It is an arithmetic number, because the mean of its divisors is an integer number (20222607721).

Almost surely, 240445215441 is an apocalyptic number.

It is an amenable number.

40445215441 is a deficient number, since it is larger than the sum of its proper divisors (1).

40445215441 is an equidigital number, since it uses as much as digits as its factorization.

40445215441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51200, while the sum is 34.

Adding to 40445215441 its reverse (14451254404), we get a palindrome (54896469845).

The spelling of 40445215441 in words is "forty billion, four hundred forty-five million, two hundred fifteen thousand, four hundred forty-one".