Base | Representation |
---|---|
bin | 10010011001010000011010… |
… | …01100010001001001011111 |
3 | 12022020000002121112001110122 |
4 | 21030220031030101021133 |
5 | 20300214024132013003 |
6 | 222010324232225155 |
7 | 11343301146054203 |
oct | 1114501514211137 |
9 | 168200077461418 |
10 | 40450223313503 |
11 | 11985930586233 |
12 | 4653635b3b1bb |
13 | 1975594003493 |
14 | 9dbb308dcb03 |
15 | 4a230a8bc238 |
hex | 24ca0d31125f |
40450223313503 has 2 divisors, whose sum is σ = 40450223313504. Its totient is φ = 40450223313502.
The previous prime is 40450223313499. The next prime is 40450223313559. The reversal of 40450223313503 is 30531332205404.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40450223313503 - 22 = 40450223313499 is a prime.
It is a super-2 number, since 2×404502233135032 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40450223313103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20225111656751 + 20225111656752.
It is an arithmetic number, because the mean of its divisors is an integer number (20225111656752).
Almost surely, 240450223313503 is an apocalyptic number.
40450223313503 is a deficient number, since it is larger than the sum of its proper divisors (1).
40450223313503 is an equidigital number, since it uses as much as digits as its factorization.
40450223313503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 35.
Adding to 40450223313503 its reverse (30531332205404), we get a palindrome (70981555518907).
The spelling of 40450223313503 in words is "forty trillion, four hundred fifty billion, two hundred twenty-three million, three hundred thirteen thousand, five hundred three".
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