Base | Representation |
---|---|
bin | 100101101011010101… |
… | …010001000000110011 |
3 | 10212102102001102010121 |
4 | 211223111101000303 |
5 | 1130323043124413 |
6 | 30330204311111 |
7 | 2631344405311 |
oct | 455325210063 |
9 | 125372042117 |
10 | 40455442483 |
11 | 16180051795 |
12 | 7a10542497 |
13 | 3a79536561 |
14 | 1d5ac850b1 |
15 | 10bb99cb8d |
hex | 96b551033 |
40455442483 has 2 divisors, whose sum is σ = 40455442484. Its totient is φ = 40455442482.
The previous prime is 40455442481. The next prime is 40455442499. The reversal of 40455442483 is 38424455404.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40455442483 - 21 = 40455442481 is a prime.
It is a super-3 number, since 3×404554424833 (a number of 33 digits) contains 333 as substring.
Together with 40455442481, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (40455442481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20227721241 + 20227721242.
It is an arithmetic number, because the mean of its divisors is an integer number (20227721242).
Almost surely, 240455442483 is an apocalyptic number.
40455442483 is a deficient number, since it is larger than the sum of its proper divisors (1).
40455442483 is an equidigital number, since it uses as much as digits as its factorization.
40455442483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1228800, while the sum is 43.
Adding to 40455442483 its reverse (38424455404), we get a palindrome (78879897887).
The spelling of 40455442483 in words is "forty billion, four hundred fifty-five million, four hundred forty-two thousand, four hundred eighty-three".
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