Base | Representation |
---|---|
bin | 1111000101010100… |
… | …0011001011101001 |
3 | 101110011120201122202 |
4 | 3301111003023221 |
5 | 31242444431423 |
6 | 1505432225545 |
7 | 202222314452 |
oct | 36125031351 |
9 | 11404521582 |
10 | 4048827113 |
11 | 1798503811 |
12 | 94bb3b2b5 |
13 | 4c6a88cb6 |
14 | 2a5a24129 |
15 | 18a6bc728 |
hex | f15432e9 |
4048827113 has 2 divisors, whose sum is σ = 4048827114. Its totient is φ = 4048827112.
The previous prime is 4048827091. The next prime is 4048827131. The reversal of 4048827113 is 3117288404.
4048827113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
Together with next prime (4048827131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2463831769 + 1584995344 = 49637^2 + 39812^2 .
It is a cyclic number.
It is not a de Polignac number, because 4048827113 - 28 = 4048826857 is a prime.
It is not a weakly prime, because it can be changed into another prime (4048827193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2024413556 + 2024413557.
It is an arithmetic number, because the mean of its divisors is an integer number (2024413557).
Almost surely, 24048827113 is an apocalyptic number.
It is an amenable number.
4048827113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4048827113 is an equidigital number, since it uses as much as digits as its factorization.
4048827113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43008, while the sum is 38.
The square root of 4048827113 is about 63630.3945689479. The cubic root of 4048827113 is about 1593.8339650383.
The spelling of 4048827113 in words is "four billion, forty-eight million, eight hundred twenty-seven thousand, one hundred thirteen".
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