Base | Representation |
---|---|
bin | 1011110010011110010… |
… | …10010101001111000111 |
3 | 1102201111222111201102211 |
4 | 11321033022111033013 |
5 | 23114023042044221 |
6 | 510025115044251 |
7 | 41156432661244 |
oct | 5711712251707 |
9 | 1381458451384 |
10 | 405055034311 |
11 | 146868009504 |
12 | 66604140687 |
13 | 2c2729c88c5 |
14 | 158676ac5cb |
15 | a80a5c16e1 |
hex | 5e4f2953c7 |
405055034311 has 2 divisors, whose sum is σ = 405055034312. Its totient is φ = 405055034310.
The previous prime is 405055034261. The next prime is 405055034341. The reversal of 405055034311 is 113430550504.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 405055034311 - 213 = 405055026119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (405055034341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202527517155 + 202527517156.
It is an arithmetic number, because the mean of its divisors is an integer number (202527517156).
Almost surely, 2405055034311 is an apocalyptic number.
405055034311 is a deficient number, since it is larger than the sum of its proper divisors (1).
405055034311 is an equidigital number, since it uses as much as digits as its factorization.
405055034311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 405055034311 its reverse (113430550504), we get a palindrome (518485584815).
The spelling of 405055034311 in words is "four hundred five billion, fifty-five million, thirty-four thousand, three hundred eleven".
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