Search a number
-
+
40511041411 is a prime number
BaseRepresentation
bin100101101110101001…
…010110111110000011
310212120021200010112011
4211232221112332003
51130431311311121
630335512113351
72632621112311
oct455651267603
9125507603464
1040511041411
11161a9477015
127a27095857
133a87c02229
141d643d90b1
1510c17d17e1
hex96ea56f83

40511041411 has 2 divisors, whose sum is σ = 40511041412. Its totient is φ = 40511041410.

The previous prime is 40511041381. The next prime is 40511041433. The reversal of 40511041411 is 11414011504.

It is an a-pointer prime, because the next prime (40511041433) can be obtained adding 40511041411 to its sum of digits (22).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 40511041411 - 25 = 40511041379 is a prime.

It is a super-2 number, since 2×405110414112 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40511041451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20255520705 + 20255520706.

It is an arithmetic number, because the mean of its divisors is an integer number (20255520706).

Almost surely, 240511041411 is an apocalyptic number.

40511041411 is a deficient number, since it is larger than the sum of its proper divisors (1).

40511041411 is an equidigital number, since it uses as much as digits as its factorization.

40511041411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 320, while the sum is 22.

Adding to 40511041411 its reverse (11414011504), we get a palindrome (51925052915).

The spelling of 40511041411 in words is "forty billion, five hundred eleven million, forty-one thousand, four hundred eleven".