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4051283023147 is a prime number
BaseRepresentation
bin111010111101000011010…
…010010001010100101011
3112100022001212202012102211
4322331003102101110223
51012334011423220042
612341044515105551
7565460366341123
oct72750322212453
915308055665384
104051283023147
111322159716a28
125551ba5a22b7
1323505a60b049
14100124211c83
15705b32da017
hex3af4349152b

4051283023147 has 2 divisors, whose sum is σ = 4051283023148. Its totient is φ = 4051283023146.

The previous prime is 4051283023141. The next prime is 4051283023153. The reversal of 4051283023147 is 7413203821504.

4051283023147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (4051283023141) and next prime (4051283023153).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4051283023147 is a prime.

It is not a weakly prime, because it can be changed into another prime (4051283023141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2025641511573 + 2025641511574.

It is an arithmetic number, because the mean of its divisors is an integer number (2025641511574).

Almost surely, 24051283023147 is an apocalyptic number.

4051283023147 is a deficient number, since it is larger than the sum of its proper divisors (1).

4051283023147 is an equidigital number, since it uses as much as digits as its factorization.

4051283023147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 161280, while the sum is 40.

The spelling of 4051283023147 in words is "four trillion, fifty-one billion, two hundred eighty-three million, twenty-three thousand, one hundred forty-seven".