Base | Representation |
---|---|
bin | 10010011011010110001100… |
… | …01111111110100001011011 |
3 | 12022110212111011111011220201 |
4 | 21031223012033332201123 |
5 | 20302403123133004413 |
6 | 222103323251003031 |
7 | 11351423054013235 |
oct | 1115530617764133 |
9 | 168425434434821 |
10 | 40522047547483 |
11 | 11a03338484297 |
12 | 466553b899477 |
13 | 197c29c374508 |
14 | a013c58d9255 |
15 | 4a41112219dd |
hex | 24dac63fe85b |
40522047547483 has 2 divisors, whose sum is σ = 40522047547484. Its totient is φ = 40522047547482.
The previous prime is 40522047547439. The next prime is 40522047547537. The reversal of 40522047547483 is 38474574022504.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40522047547483 - 225 = 40522013993051 is a prime.
It is not a weakly prime, because it can be changed into another prime (40522047547283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20261023773741 + 20261023773742.
It is an arithmetic number, because the mean of its divisors is an integer number (20261023773742).
Almost surely, 240522047547483 is an apocalyptic number.
40522047547483 is a deficient number, since it is larger than the sum of its proper divisors (1).
40522047547483 is an equidigital number, since it uses as much as digits as its factorization.
40522047547483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30105600, while the sum is 55.
The spelling of 40522047547483 in words is "forty trillion, five hundred twenty-two billion, forty-seven million, five hundred forty-seven thousand, four hundred eighty-three".
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