Base | Representation |
---|---|
bin | 111010111110001110110… |
… | …101000001110111111111 |
3 | 112100102100012120221110100 |
4 | 322332032311001313333 |
5 | 1012344110402113421 |
6 | 12341414352012143 |
7 | 565533656155365 |
oct | 72761665016777 |
9 | 15312305527410 |
10 | 4052550426111 |
11 | 132274a07a5a0 |
12 | 5554b2b31053 |
13 | 235200071c25 |
14 | 100204689635 |
15 | 706396dbc26 |
hex | 3af8ed41dff |
4052550426111 has 96 divisors (see below), whose sum is σ = 6897387893760. Its totient is φ = 2265254784000.
The previous prime is 4052550426109. The next prime is 4052550426149. The reversal of 4052550426111 is 1116240552504.
4052550426111 is a `hidden beast` number, since 4 + 0 + 5 + 2 + 550 + 42 + 61 + 1 + 1 = 666.
It is not a de Polignac number, because 4052550426111 - 21 = 4052550426109 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4052550426101) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 74810886 + ... + 74865036.
It is an arithmetic number, because the mean of its divisors is an integer number (71847790560).
Almost surely, 24052550426111 is an apocalyptic number.
4052550426111 is a deficient number, since it is larger than the sum of its proper divisors (2844837467649).
4052550426111 is a wasteful number, since it uses less digits than its factorization.
4052550426111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55077 (or 55074 counting only the distinct ones).
The product of its (nonzero) digits is 48000, while the sum is 36.
Adding to 4052550426111 its reverse (1116240552504), we get a palindrome (5168790978615).
The spelling of 4052550426111 in words is "four trillion, fifty-two billion, five hundred fifty million, four hundred twenty-six thousand, one hundred eleven".
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