Search a number
-
+
405269421251 is a prime number
BaseRepresentation
bin1011110010110111111…
…00001001110011000011
31102202001220220201000212
411321123330021303003
523114442432440001
6510102254104335
741164645146122
oct5713374116303
91382056821025
10405269421251
111469680285a2
1266663aab0ab
132c2a824c496
1415887d57ab9
15a81e31d7bb
hex5e5bf09cc3

405269421251 has 2 divisors, whose sum is σ = 405269421252. Its totient is φ = 405269421250.

The previous prime is 405269421217. The next prime is 405269421253. The reversal of 405269421251 is 152124962504.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 405269421251 - 214 = 405269404867 is a prime.

It is a super-2 number, since 2×4052694212512 (a number of 24 digits) contains 22 as substring.

Together with 405269421253, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 405269421199 and 405269421208.

It is not a weakly prime, because it can be changed into another prime (405269421253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202634710625 + 202634710626.

It is an arithmetic number, because the mean of its divisors is an integer number (202634710626).

Almost surely, 2405269421251 is an apocalyptic number.

405269421251 is a deficient number, since it is larger than the sum of its proper divisors (1).

405269421251 is an equidigital number, since it uses as much as digits as its factorization.

405269421251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 172800, while the sum is 41.

The spelling of 405269421251 in words is "four hundred five billion, two hundred sixty-nine million, four hundred twenty-one thousand, two hundred fifty-one".