Search a number
-
+
40531144231 is a prime number
BaseRepresentation
bin100101101111110110…
…000010111000100111
310212121200111110102001
4211233312002320213
51131001433103411
630341511030131
72633254020154
oct455766027047
9125550443361
1040531144231
1116209857616
127a3196b347
133a8c1203a6
141d66d4d22b
1510c3452dc1
hex96fd82e27

40531144231 has 2 divisors, whose sum is σ = 40531144232. Its totient is φ = 40531144230.

The previous prime is 40531144219. The next prime is 40531144271. The reversal of 40531144231 is 13244113504.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 40531144231 - 213 = 40531136039 is a prime.

It is a super-2 number, since 2×405311442312 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 40531144231.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (40531144211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20265572115 + 20265572116.

It is an arithmetic number, because the mean of its divisors is an integer number (20265572116).

Almost surely, 240531144231 is an apocalyptic number.

40531144231 is a deficient number, since it is larger than the sum of its proper divisors (1).

40531144231 is an equidigital number, since it uses as much as digits as its factorization.

40531144231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 40531144231 its reverse (13244113504), we get a palindrome (53775257735).

The spelling of 40531144231 in words is "forty billion, five hundred thirty-one million, one hundred forty-four thousand, two hundred thirty-one".