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405330140032501 is a prime number
BaseRepresentation
bin101110000101001010100011…
…1000000110110110111110101
31222011011011221101002120011011
41130022111013000312313311
5411111412111322020001
63554022032402112221
7151243064504443045
oct13412250700666765
91864134841076134
10405330140032501
11108172602127a22
123956384394b671
1314522611824a78
147214124dcd725
1531cd879098d51
hex170a547036df5

405330140032501 has 2 divisors, whose sum is σ = 405330140032502. Its totient is φ = 405330140032500.

The previous prime is 405330140032453. The next prime is 405330140032541. The reversal of 405330140032501 is 105230041033504.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 333579905788900 + 71750234243601 = 18264170^2 + 8470551^2 .

It is a cyclic number.

It is not a de Polignac number, because 405330140032501 - 219 = 405330139508213 is a prime.

It is a super-3 number, since 3×4053301400325013 (a number of 45 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (405330140032541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 202665070016250 + 202665070016251.

It is an arithmetic number, because the mean of its divisors is an integer number (202665070016251).

Almost surely, 2405330140032501 is an apocalyptic number.

It is an amenable number.

405330140032501 is a deficient number, since it is larger than the sum of its proper divisors (1).

405330140032501 is an equidigital number, since it uses as much as digits as its factorization.

405330140032501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 31.

The spelling of 405330140032501 in words is "four hundred five trillion, three hundred thirty billion, one hundred forty million, thirty-two thousand, five hundred one".